Question

Integrale di arctan(2x) dx ?

Answer 1

∫arctan(2x) dx

Poniamo:

g'(x)=1 e f(x)= arctan(2x)

∫arctan(2x) dx =x (arctang(2x))-∫x [x/(1+4x^2)] (2) dx =x (arctang(2x))-1/4 ∫8x/(4x^2+1) dx=

=x (arctang(2x))-1/4 ln(4x^2+1) + c

Answer 2

§arctg(2x)= xarctg(2x) - § x(2/(1+4x^2)= // - 1/4 § 8x/(4x^2 +1)= // - log(4x^2+1)=

= xarctg(2x) - log(4x^2+1)/4 +c

Bravo Bruno :D

Answer 3

Vendita Cialis In Svizzera

Answer 4

https://buytadalafshop.com/ - cialis 10mg

Answer 5

<a href=https://buypropeciaon.com/>cheap propecia 10mg</a>

Answer 6

<a href=http://buystromectolon.com/>buy ivermectin stromectol</a>

Answer 7

Buy Nexium Usa

Answer 8

https://buypropeciaon.com/ - finpecia uk

Answer 9

<a href=http://buytadalafshop.com/>cialis from india</a>

Answer 10

Order Propecia Online From Canada